Question

3 x (x+1)-2x (5x+3) = 7х (2-x)+34​

Answer 1

Ответ:

3х²+3х-10х²-6х=14х-7х²+34

-7х²-3х=14х-7х²+34

-17х=34

-х=2

х=2

Answer 2

To solve the given equation, let's simplify both sides step by step:

3(x + 1) - 2x(5x + 3) = 7x(2 - x) + 34

First, distribute the terms on both sides:

3x + 3 - 10x^2 - 6x = 14x - 7x^2 + 34

Combine like terms:

3x - 10x^2 - 6x = 14x - 7x^2 + 34

Now, let's bring all the terms to one side of the equation by subtracting the right side from both sides:

3x - 10x^2 - 6x - 14x + 7x^2 - 34 = 0

Combine like terms again:

-10x^2 + 4x^2 - 17x - 34 = 0

Combine the x^2 terms and the constant terms:

-6x^2 - 17x - 34 = 0

At this point, we have a quadratic equation. To solve it, we can either factor it or use the quadratic formula. Let's use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In our case, a = -6, b = -17, and c = -34. Substituting these values into the formula, we get:

x = (-(-17) ± √((-17)^2 - 4(-6)(-34))) / (2(-6))

Simplifying further:

x = (17 ± √(289 - 408)) / (-12) x = (17 ± √(-119)) / (-12)

Since we have a negative value under the square root, this equation has no real solutions.