Question

1)-(-(-(-(-a)))),если а =-50;9,09;-20 10/13

Answer 1

Ответ:50;-0.09;20 10/13

Пошаговое объяснение:

А=-50

-(-(-(-(-(-50)))))

-(-(-(-(50))))

-(-(-(-50)))

-(-(50))

50

А=9

-(-(-(-(-9,09))))

-(-(-(9,09)))

-(-(-9,09))

-(9,09)

-9,09

А=-20

-(-(-(-(-(-20 10/13)))))

-(-(-(-(20 10/13))))

-(-(-(-20 10/13)))

-(-(20 10/13))

-(-20 10/13)

20 10/13

Answer 2

Ответ:

50, - 9, - 09, 20, - 10/13

Answer 3

To evaluate the expression 1)-(-(-(-(-a)))) with the given values of a, we can substitute each value of a into the expression and simplify step by step.

1. For a = -50: 1)-(-(-(-(-a)))) = 1)-(-(-(-(-(-50))))) = 1)-(-(-(-50))) = 1)-(-(-50)) = 1)-(-50) = 1) + 50 = 51

2. For a = 9.09: 1)-(-(-(-(-a)))) = 1)-(-(-(-(-9.09)))) = 1)-(-(-(-9.09))) = 1)-(-(-9.09)) = 1)-(-9.09) = 1) + 9.09 = 10.09

3. For a = -20 10/13: To evaluate this mixed number, we need to convert it to an improper fraction: -20 10/13 = -(20 * 13 + 10)/13 = -(270 + 10)/13 = -280/13

Now we substitute this value into the expression: 1)-(-(-(-(-a)))) = 1)-(-(-(-(-(-280/13))))) = 1)-(-(-(-(-(-280/13))))) = 1)-(-(-(-(-(-(-280/13)))))) = 1)-(-(-(-(-(-(-280/13)))))) = 1)-(-(-(-(-(-(-(-280/13))))))) = 1)-(-(-(-(-(-(-(-(-280/13)))))))) = 1)-(-(-(-(-(-(-(-(-280/13)))))))) = 1)-(-(-(-(-(-(-(-(-(-280/13))))))))) = 1)-(-(-(-(-(-(-(-(-(-(-280/13)))))))))) = 1)-(-(-(-(-(-(-(-(-(-(-(-280/13))))))))))) = 1)-(-(-(-(-(-(-(-(-(-(-(-(-280/13)))))))))))) = 1)-(-(-(-(-(-(-(-(-(-(-(-(-(-(-280/13)))))))))))))) Here, we can observe that there are 14 negative signs, so the expression simplifies to: 1)-(-(-(-(-(-(-(-(-(-(-(-(-(-(-280/13)))))))))))))) = 1) + (-280/13) = 1 - (280/13) = (13/13) - (280/13) = -267/13

Therefore, for a = -20 10/13, the value of the expression is -267/13.

In summary: For a = -50, the expression evaluates to 51. For a = 9.09, the expression evaluates to 10.09. For a = -20 10/13, the expression evaluates to -267/13.