Question

(x^2+x-1)(x^2+x+3)=20

Answer 1

Ответ:

фото..................

Answer 2

To solve the equation (x^2+x-1)(x^2+x+3) = 20, we can expand the left side of the equation and rearrange it to form a quadratic equation. Here's how you can do it step by step:

1. Expand the left side of the equation: (x^2+x-1)(x^2+x+3) = 20 x^4 + 2x^3 + 3x^2 - x^2 - x - 3 = 20 x^4 + 2x^3 + 2x^2 - x - 23 = 0

2. Rearrange the equation to form a quadratic equation: x^4 + 2x^3 + 2x^2 - x - 23 = 0 x^4 + 2x^3 + 2x^2 = x + 23

3. Subtract 23 from both sides of the equation to move the constant to the right side: x^4 + 2x^3 + 2x^2 - x - 23 - 23 = x + 23 - 23 x^4 + 2x^3 + 2x^2 - x - 46 = x

4. Combine like terms: x^4 + 2x^3 + 2x^2 - x - x = x + 46 x^4 + 2x^3 + 2x^2 - 2x - 46 = 0

At this point, we have transformed the given equation into the form of a quartic equation, which is a polynomial equation of degree 4. Solving quartic equations can be complex and often requires advanced mathematical techniques. In this case, finding the exact analytical solution may not be straightforward.

You can use numerical methods or software to approximate the solutions to this equation.