Question

90!•29!89!•30! как сделать?​

Answer 1

Ответ:

Пошаговое объяснение:

1485715964481761497309522733620825737885569961284688766942216863704985393094065876545992131370884059645617234469978112000000000000000000000 * 8841761993739701954543616000000 =13136346948247163751425922409767617249500972470596909325476118523933146801183665878475571317770162531372257208877052095065328038317262469332992000000000000000000000000000

16507955160908461081216919262453619309839666236496541854913520707833171034378509739399912570787600662729080382999756800000000000000000000 * 265252859812191058636308480000000 =4378782316082387917141974136589205749833657490198969775158706174644382267061221959491857105923387510457419069625684031688442679439087489777664000000000000000000000000000

Answer 2

To calculate the value of the expression $90! \cdot 29! \cdot 89! \cdot 30!$, you need to find the factorial of each number and then multiply them together. However, since these numbers are very large, it is practically impossible to compute their exact values manually.

Factorials grow very quickly, and even using a calculator, you might encounter issues with precision or memory limits. Instead, you can use scientific notation or logarithms to get an approximate value of the expression.

If you're interested in the approximate value, you can use the following steps:

Step 1: Take the logarithm of each factorial term to convert the multiplication into an addition operation: $\log(90!) + \log(29!) + \log(89!) + \log(30!)$

Step 2: Use a calculator to compute the sum of the logarithms.

Step 3: Take the antilogarithm (exponentiate) of the result to get the approximate value.

Keep in mind that even with this approach, the numbers involved are extremely large, and the result will be a very large number as well.