Question

(n+3):4=1 д) 15:р+1=16

Answer 1

$(n + 3) \div 4 = 1 \\ n + 3 = 1 \: \times \: 4 \\ n + 3 = 4 \\ n = 4 - 3 \\ n = 1$

$15 \div p + 1 = 16 \\ p + 1 = 16 \times 15 \\ p + 1 = 240 \\ p = 240 - 1 \\ p = 239$

Answer 2

To solve the equations:

a) (n + 3) / 4 = 1

To isolate n, we can multiply both sides of the equation by 4:

4 * (n + 3) / 4 = 1 * 4 n + 3 = 4

Now, we can isolate n by subtracting 3 from both sides:

n + 3 - 3 = 4 - 3 n = 1

Therefore, the solution to the equation (n + 3) / 4 = 1 is n = 1.

b) 15 / (r + 1) = 16

To isolate r, we can multiply both sides of the equation by (r + 1):

15 = 16 * (r + 1)

Now, we can distribute the 16:

15 = 16r + 16

Next, we can isolate the variable term by subtracting 16 from both sides:

15 - 16 = 16r + 16 - 16 -1 = 16r

Finally, we can solve for r by dividing both sides by 16:

-1 / 16 = 16r / 16 r = -1/16

Therefore, the solution to the equation 15 / (r + 1) = 16 is r = -1/16.