Question

(3a-8)(9a+7)-(27a-1)(a+1)=3

Answer 1

Ответ:

$-\frac{58}{77}$

Пошаговое объяснение:

$(3a-8)(9a+7)-(27a-1)(a+1)=3\\27a^2-72a+21a-56-(27a^2-a+27a-1)=3\\\27a^2-51a-56-(27a^2+26a-1)=3\\27a^2-51a-56-27a^2-26a+1=3\\-77a-55=3\\-77a=3+55\\-77a=58\\a=-\frac{58}{77}$

Answer 2

To solve the equation (3a-8)(9a+7) - (27a-1)(a+1) = 3, we can start by expanding the terms on both sides of the equation and then simplifying.

Expanding the left side: (3a-8)(9a+7) = 27a^2 + 21a - 72a - 56

Expanding the right side: (27a-1)(a+1) = 27a^2 + 27a - a - 1

Now we can substitute these expansions back into the original equation:

(27a^2 + 21a - 72a - 56) - (27a^2 + 27a - a - 1) = 3

Simplifying further: 27a^2 + 21a - 72a - 56 - 27a^2 - 27a + a + 1 = 3

Combining like terms: -56 - 56a = 3

To isolate the variable, we move -56 to the right side: -56a = 3 + 56

Simplifying: -56a = 59

Finally, we solve for 'a' by dividing both sides by -56: a = 59 / -56

Therefore, the solution to the equation (3a-8)(9a+7) - (27a-1)(a+1) = 3 is a = -59/56.