Question

12 а-1=-а +25 2 - с =5с + 1 2х + 3б = -7 + 2b -3d -10= 3d-6 3y - 3 =5 - y

Answer 1

Пошаговое объяснение:

вот вроде так смотри щас ещё скину

Answer 2

To solve the given system of equations, let's go through each equation one by one:

1. 12а - 1 = -а + 25

To solve for 'а', we'll simplify and isolate the variable: 12а + а = 25 + 1 13а = 26 а = 26 / 13 а = 2

So the value of 'а' is 2.

2. 2 - с = 5с + 1

Let's simplify and solve for 'с': 2 - 1 = 5с + с 1 = 6с с = 1 / 6

Therefore, the value of 'с' is 1/6.

3. 2х + 3б = -7 + 2b

We'll solve for 'х' in terms of 'b': 2х - 2b = -7 - 3б 2(х - b) = -7 - 3б х - b = (-7 - 3б) / 2

4. -3d - 10 = 3d - 6

We'll solve for 'd': -3d - 3d = -6 + 10 -6d = 4 d = 4 / -6 d = -2/3

So the value of 'd' is -2/3.

5. 3y - 3 = 5 - y

We'll solve for 'y': 3y + y = 5 + 3 4y = 8 y = 8 / 4 y = 2

Therefore, the value of 'y' is 2.

To summarize, the solutions to the given system of equations are: а = 2 с = 1/6 х = (-7 - 3б) / 2 (in terms of 'b') d = -2/3 y = 2