Question

3x(x+y+c)-3y(x-y-c)-3c(x+y-c)=​

Answer 1

Ответ:

3x^2+3y^2+3c^2

Пошаговое объяснение:

1) 3x^2+3xy+3xc-3xy+3y^2+3yc-3xc-3yc+3c^2

2)3x^2+3y^2+3c^2

Answer 2

To simplify the given expression, let's expand and collect like terms:

3x(x + y + c) - 3y(x - y - c) - 3c(x + y - c)

Expanding each term, we get:

3x^2 + 3xy + 3cx - 3xy + 3y^2 + 3cy - 3cx - 3y^2 - 3cy

Combining like terms, we can simplify further:

(3x^2 - 3y^2) + (3xy - 3xy) + (3cx - 3cx) + (3cy - 3cy)

Notice that the terms (3xy - 3xy), (3cx - 3cx), and (3cy - 3cy) will cancel out because they have opposite signs and the same coefficients.

Simplifying the remaining terms, we have:

3x^2 - 3y^2

Therefore, the simplified expression is 3x^2 - 3y^2.