Question

(2a+2b)+2*(b+c)+(c+a)*2 a+b+c=8

Answer 1

Ответ:

Пошаговое объяснение:

Раскрываем скобки

2a+2b+2b+2c+2c+2a+a+b+c=5a+5b+5c

Answer 2

To solve the given expression (2a+2b)+2*(b+c)+(c+a)*2 with the condition a+b+c=8, we can substitute the value of a+b+c into the expression and then simplify it.

Given: a+b+c = 8

Expression to solve: (2a+2b)+2*(b+c)+(c+a)*2

Substitute a+b+c into the expression: (2a+2b)+2*(b+c)+(c+a)2 = (2a+2b)+2(b+c)+(8)*2

Now, we can simplify the expression further: = 2a + 2b + 2(b + c) + 16 = 2a + 2b + 2b + 2c + 16 = 2a + 4b + 2c + 16

However, we can't determine the exact value of the expression without knowing the specific values of 'a', 'b', and 'c'. If you have specific values for 'a', 'b', and 'c', you can plug them into the simplified expression to get the final result.