Question

Logo,2 (2x - 3)+ logo,2 7 = logo,2 28.​

Answer 1

Ответ:

$3,5$

Пошаговое объяснение:

$log_{0,2}(2x-3)+log_{0,2}7=log_{0,2}28\\\\2x-3>0\\2x>3\\x>1,5\\\\log_{0,2}(2x-3)=log_{0,2}28-log_{0,2}7\\log_{0,2}(2x-3)=log_{0,2}(28/7)\\log_{0,2}(2x-3)=log_{0,2}4\\2x-3=4\\2x=7\\x=3,5\;\;\;(>1,5)$

Answer 2

To solve the equation "Logo,2 (2x - 3) + Logo,2 7 = Logo,2 28," we can use a substitution method. Let's assume that "Logo,2" represents a specific function or operation. Since I don't have any specific information about what "Logo,2" represents, I can't provide an exact solution. However, I can guide you through the general steps to solve the equation.

Let's substitute "Logo,2" with a variable, say "y," for simplicity. The equation becomes:

y(2x - 3) + y(7) = y(28)

Simplifying this equation, we have:

2xy - 3y + 7y = 28y

Combining like terms, we get:

2xy + 4y = 28y

Next, let's isolate the variable terms on one side of the equation and the constant terms on the other side. Subtracting 28y from both sides:

2xy + 4y - 28y = 0

Simplifying:

2xy - 24y = 0

Now, we can factor out the common factor of y:

y(2x - 24) = 0

To find the possible solutions, we set each factor equal to zero:

y = 0 or 2x - 24 = 0

For y = 0, it means that "Logo,2" is zero, which might not be a valid solution, depending on what "Logo,2" represents.

For 2x - 24 = 0, we solve for x:

2x = 24 x = 12

So, one possible solution is x = 12, assuming "Logo,2" represents an operation that can be cancelled out by multiplication or division. If you have any specific information about "Logo,2," please provide more details, and I can assist you further.