Question

A) 4x² = 9; б)7x2 – 5x = 0; B)2x² – 3x+5=0.РЕШИТЕ уровнения!!!​

Answer 1

А) 0,5625
Б)2,8
В)-5
Решение:
16х=9
х=0,5625

7•2=14
14-5х=0
5х=14
х=2,8

4х-3х=х
х+5=0
х=-5

Answer 2

To solve the equations, let's find the values of 'x' that satisfy each equation:

A) 4x² = 9

Step 1: Divide both sides by 4 to isolate x²: x² = 9/4

Step 2: Take the square root of both sides to solve for x: x = ±√(9/4) x = ±(3/2)

So the solutions for equation A are: x = 3/2 and x = -3/2

B) 7x² - 5x = 0

Step 1: Factor out the common term 'x' from the equation: x(7x - 5) = 0

Step 2: Set each factor to zero and solve for x:

1. x = 0
2. 7x - 5 = 0 7x = 5 x = 5/7

So the solutions for equation B are: x = 0 and x = 5/7

C) 2x² - 3x + 5 = 0

We can solve this equation using the quadratic formula, which is given by:

x = (-b ± √(b² - 4ac)) / 2a

where 'a', 'b', and 'c' are coefficients of the quadratic equation (ax² + bx + c = 0).

For equation C, a = 2, b = -3, and c = 5:

x = [-( -3) ± √((-3)² - 4 * 2 * 5)] / (2 * 2) x = (3 ± √(9 - 40)) / 4 x = (3 ± √(-31)) / 4

Since the discriminant (√(b² - 4ac)) is negative, this quadratic equation has complex solutions. So the solutions for equation C are:

x = (3 + √31i) / 4 and x = (3 - √31i) / 4

Please note that 'i' represents the imaginary unit (√(-1)). Complex solutions involve both real and imaginary parts.