Question

Y=5-2x-x^2 F(3); f(-2) (k;-10)

Answer 1

Ответ:

f(3)=5-2*3-3*3=5-6-9=-10

f(-2)=5-2*(-2)-(-3)*(-3)=5+6-9=2

(2;-10)

Answer 2

It looks like you are dealing with a quadratic function in the form of f(x) = -x^2 - 2x + 5. Let's evaluate the function at specific values of x.

1. To find f(3), we plug x = 3 into the function: f(3) = -(3)^2 - 2(3) + 5 f(3) = -9 - 6 + 5 f(3) = -10

So, f(3) equals -10.

2. To find f(-2), we plug x = -2 into the function: f(-2) = -(-2)^2 - 2(-2) + 5 f(-2) = -4 + 4 + 5 f(-2) = 5

So, f(-2) equals 5.

3. It seems you provided an additional point (k, -10) without mentioning what you would like to find. If you want to find the value of k, we can use the given information that f(k) = -10: -10 = -k^2 - 2k + 5 Rearrange the equation to find k: k^2 + 2k - 15 = 0 Now, we can solve for k using the quadratic formula or factoring. Factoring gives us: (k + 5)(k - 3) = 0 This equation is satisfied when either k + 5 = 0 or k - 3 = 0. So, there are two possible values for k: k = -5 or k = 3.

If you need further assistance or have any other questions, feel free to ask!