Question

Найти производную y=e^x + arccos - 4x^3

Answer 1

Ответ:

Пошаговое объяснение:

y'=e^x- 1 /V1-x^2-12x^2,   1-x^2  стоит под корнем

Answer 2

To find the derivative of the given function $y = e^x + \arccos(x) - 4x^3$, we need to differentiate each term with respect to $x$ using the rules of differentiation. Let's find the derivative step by step:

1. The derivative of $e^x$ with respect to $x$ is simply $e^x$.

2. The derivative of $\arccos(x)$ with respect to $x$ is $-\frac{1}{\sqrt{1-x^2}}$.

3. The derivative of $4x^3$ with respect to $x$ is $12x^2$.

Putting it all together, the derivative of the given function $y$ is:

$y' = \frac{dy}{dx} = e^x - \frac{1}{\sqrt{1-x^2}} - 12x^2$

So the derivative of $y$ is $e^x - \frac{1}{\sqrt{1-x^2}} - 12x^2$.