Question

9x^2+12x+4=0 pleaseeee​

Answer 1

Ответ:

Вот ответ. Всё как есть!!

Answer 2

Пошаговое объяснение:

(3x+2) ^2=0

3x+2=0

3x=-2

X=-2/3(-0,6)

Answer 3

To solve the quadratic equation $9x^2 + 12x + 4 = 0$, we can use the quadratic formula. The quadratic formula states that for any quadratic equation of the form $ax^2 + bx + c = 0$, the solutions for $x$ are given by:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In our case, $a = 9$, $b = 12$, and $c = 4$. Plugging these values into the quadratic formula, we get:

$x = \frac{-12 \pm \sqrt{12^2 - 4 \cdot 9 \cdot 4}}{2 \cdot 9}$

Now, let's calculate the discriminant ($b^2 - 4ac$):

$b^2 - 4ac = 12^2 - 4 \cdot 9 \cdot 4 = 144 - 144 = 0$

Since the discriminant is zero, there will be only one real solution for $x$:

$x = \frac{-12}{2 \cdot 9} = \frac{-12}{18} = -\frac{2}{3}$

So, the solution to the quadratic equation $9x^2 + 12x + 4 = 0$ is $x = -\frac{2}{3}$.