Question

Двумя косилками за 6 часов скосили траву с площадью 36 гектаров За какое время скорость отрыва 1 косилка с площадью 27 гектара

Answer 1

Ответ:

Пошаговое объяснение:

36:6 = 6 (га) - за 1 час две косилки

6:2 = 3 (га) - за 1 час одна косилка

27:3 = 9 (час) - одна косилка 27 гектаров

Answer 2

To solve this problem, we can use the concept of the rate of work. The rate of work is the amount of work done per unit of time. In this case, we know that two mowers together can mow 36 hectares in 6 hours. Let's calculate the combined rate of the two mowers:

Combined rate = Total area / Time taken = 36 hectares / 6 hours = 6 hectares per hour

Now, we want to find the time it takes for one mower to mow an area of 27 hectares. Let's call the time taken by one mower to mow 27 hectares as "t" hours.

Rate of one mower = Area / Time taken = 27 hectares / t hours

Since the rate of work is the same, we can equate the two rates:

6 hectares per hour = 27 hectares / t hours

Now, we can solve for "t":

t = 27 hectares / 6 hectares per hour t = 4.5 hours

So, it will take one mower 4.5 hours to mow an area of 27 hectares.