Question

2(x-3) + 2х≤ 4X-8 < 6x+ 3.​

Answer 1

Ответ:

надеюсь смогла помочь тебе,если не трудно поставь лучший ответ

Answer 2

To solve the inequality 2(x-3) + 2x ≤ 4x - 8 < 6x + 3, we'll do it step by step.

Step 1: Solve the left part of the inequality: 2(x-3) + 2x ≤ 4x - 8 Step 2: Solve the right part of the inequality: 4x - 8 < 6x + 3

Step 1: 2(x-3) + 2x ≤ 4x - 8

First, distribute the 2 on the left side: 2x - 6 + 2x ≤ 4x - 8

Combine like terms: 4x - 6 ≤ 4x - 8

Now, subtract 4x from both sides to isolate the variable: 4x - 4x - 6 ≤ 4x - 4x - 8 -6 ≤ -8

This inequality is not possible because -6 is greater than -8. There is no solution for this part of the inequality.

Step 2: 4x - 8 < 6x + 3

First, subtract 4x from both sides to move all x terms to one side: 4x - 4x - 8 < 6x - 4x + 3 -8 < 2x + 3

Next, subtract 3 from both sides to isolate the variable: -8 - 3 < 2x + 3 - 3 -11 < 2x

Finally, divide both sides by 2 to find the final solution: -11/2 < x

So, the solution for the inequality is: -11/2 < x.

Please note that since the left part of the original inequality had no solution, the solution is only given for the right part.