Question

-(с+3)+(b-2)-(a-c)знайти значення ,якщо a=16;b=21;c=-51/8

Answer 1

Ответ:

Пошаговое объяснение:

=-с-3+b-2-a+c=b-5-a

21-5-16=0

Answer 2

Ответ:

0

Пошаговое объяснение:

$- ( c + 3) + (b - 2) - (a - c) \\ - ( - \frac{51}{8} + 3) + (21 - 2) - (16 - \frac{51}{8} ) \\ \frac{51}{8} - 3 +19 - 16 + \frac{51}{8} = 19 - 16 - 3 = 0$

Answer 3

To find the value of the expression -(с+3)+(b-2)-(a-c) with the given values a=16, b=21, and c=-51/8, we simply substitute the values and perform the arithmetic operations step by step:

Expression = -(с+3) + (b-2) - (a-c)

Substitute the given values: Expression = -( (-51/8) + 3) + (21-2) - (16-(-51/8))

Now, perform the arithmetic operations: Expression = -( (-51/8 + 24/8) ) + (19) - (16 + 51/8)

Expression = -( -27/8 ) + 19 - ( 128/8 + 51/8 )

Expression = (27/8) + 19 - ( 179/8 )

Expression = (27/8) + 19 - ( 179/8 )

Now, find a common denominator for (27/8) and (179/8), which is 8: Expression = (27/8) + (152/8) - ( 179/8 )

Now, add the fractions: Expression = (27 + 152 - 179)/8

Expression = 0/8

Finally, the value of the expression is 0.