Question

(4z +...)(4z-...)=16z-1​

Answer 1

Ответ:

Пошаговое объяснение:

(4z+1)(4z-1)= 16z²-1

Answer 2

(4z + 1) * (4z - 1) = 16z² - 1

© Rahmann.

Answer 3

To solve the equation, we need to fill in the missing terms in the expressions (4z + ...) and (4z - ...) and find the values that satisfy the equation (4z + ...)(4z - ...) = 16z - 1.

Let's expand the left side of the equation using the distributive property:

(4z + ...)(4z - ...) = 16z - 1

Expanding the left side:

(16z^2 + 4z(...) - 4z(...) - ...) = 16z - 1

Simplifying further:

16z^2 + 4z(...) - 4z(...) - ... = 16z - 1

Since the equation is equal on both sides, the coefficients of the corresponding terms must be equal. We have:

16z^2 = 16z (coefficient of z^2 terms) 4z(...) - 4z(...) = 16z - 1 (coefficient of z terms) ... = -1 (constant terms)

From the first equation, we can divide both sides by 16z:

z = 1

Substituting z = 1 into the second equation:

4z(...) - 4z(...) = 16z - 1 4(...) - 4(...) = 16 - 1 4(...) - 4(...) = 15

Since the left side of the equation is a difference between two expressions, and the right side is a constant, we can conclude that the expressions must cancel each other out. In this case, the terms should be:

4(...) - 4(...) = 15 4(-15) - 4(0) = 15 -60 = 15

However, this leads to a contradiction, so there are no values for the missing terms that satisfy the equation (4z + ...)(4z - ...) = 16z - 1.