Question

(1\1\18+2х) ÷2\3=4\1\3

Answer 1

Ответ:

41/36

Пошаговое объяснение:

(11/18 + 2X) : 2/3 = 4 1/3

11/18 : 2/3 + 2X : 2/3 = 4 1/3

11/18 x 3/2 + 2X x 3/2 = 13/3

33/36 + 6/2 X = 13/3

6/2 X = 13/3 - 33/36

6/2 X = 13/3 - 11/12

3 X = 52/12 - 11/12

3 X = 41/12

X = 41/12 : 3 = 41/12 x 1/3 = 41/36

Answer 2

To solve the expression, we need to follow the order of operations, which is usually abbreviated as PEMDAS: Parentheses, Exponents, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right).

The expression you provided is not entirely clear due to the format, but I will assume that you meant the following:

(1/1/18 + 2x) ÷ 2/3 = 4/1/3

To make it easier to understand, I'll convert the mixed numbers to improper fractions:

(1 + 2x) ÷ (2/3) = 4 + 1/3

Now, we'll solve the expression step-by-step:

1. Solve the numerator: 1 + 2x

2. Solve the denominator: 2/3

3. Divide the numerator by the denominator: (1 + 2x) ÷ (2/3)

To divide by a fraction, we can multiply by its reciprocal (invert the fraction):

(1 + 2x) ÷ (2/3) = (1 + 2x) * (3/2)

Now, distribute the multiplication:

(1 + 2x) * (3/2) = 1 * (3/2) + 2x * (3/2) = 3/2 + 6x/2 = 3/2 + 3x

4. Now, set the result equal to 4 + 1/3:

3/2 + 3x = 4 + 1/3

To simplify further, let's convert 4 to an improper fraction:

4 = 4 * (3/3) = 12/3

So the equation becomes:

3/2 + 3x = 12/3 + 1/3

Now, we have a common denominator (3) for both sides:

3/2 + 3x = 13/3

5. Now, solve for x:

Subtract 3/2 from both sides to isolate 3x:

3x = 13/3 - 3/2

To add or subtract fractions, we need to have the same denominator. In this case, the common denominator is 6:

3x = (213 - 33) / 6 3x = (26 - 9) / 6 3x = 17 / 6

Finally, divide both sides by 3 to solve for x:

x = 17 / (3 * 6) x = 17 / 18

So the value of x is 17/18.