Question

5) (x + 5y + 2 = 0,10,5x – y– 6 = 0;​

Answer 1

Ответ:

х+5у= -2

Пошаговое объяснение:

х+5у+2-2=0-2

х+5у=0-2

х+5у= -2

Answer 2

It seems like you've provided a system of two linear equations:

1. $x + 5y + 2 = 0$
2. $5x - y - 6 = 0$

You can solve this system of equations by using various methods, such as substitution or elimination. Let's solve it using the substitution method.

Step 1: Solve one of the equations for one variable. Let's solve equation 2 for $y$: $5x - y - 6 = 0$ $y = 5x - 6$

Step 2: Substitute the value of $y$ from equation 2 into equation 1: $x + 5y + 2 = 0$ $x + 5(5x - 6) + 2 = 0$ $x + 25x - 30 + 2 = 0$ $26x - 28 = 0$

Step 3: Solve for $x$: $26x = 28$ $x = \frac{28}{26}$ $x = \frac{14}{13}$

Step 4: Substitute the value of $x$ back into equation 2 to find $y$: $y = 5x - 6$ $y = 5 \cdot \frac{14}{13} - 6$ $y = \frac{70}{13} - \frac{78}{13}$ $y = -\frac{8}{13}$

So, the solution to the system of equations is $x = \frac{14}{13}$ and $y = -\frac{8}{13}$.