Question

F(x)=cosx, x0 =- п÷4​

Answer 1

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Answer 2

It seems like there might be a typo or some formatting issues in your input regarding the value of x₀. However, I'll assume you're asking about a function $f(x) = \cos(x)$ and a specific value $x_0 = -\frac{\pi}{4}$.

If that's the case, then you're interested in finding the value of the cosine function $\cos(x)$ at $x = -\frac{\pi}{4}$. Plugging in the value, you have:

$f\left(-\frac{\pi}{4}\right) = \cos\left(-\frac{\pi}{4}\right)$

Remember that $\cos(-x) = \cos(x)$, which means that $\cos\left(-\frac{\pi}{4}\right) = \cos\left(\frac{\pi}{4}\right)$.

Since $\cos\left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2}$, the value of $f\left(-\frac{\pi}{4}\right)$ is also $\frac{\sqrt{2}}{2}$.