Question

Уравнение1971+ x /7= 2129​

Answer 1

Ответ:

1106

Пошаговое объяснение:

1971+х:7=2129

х:7=2129-1971

х:7=158

х=158*7

х=1106

проверка

1971+1106:7=2129

1971+158=2129

2129=2129

Answer 2

1971+ х: 7= 2129

х: 7= 2129- 1971

х:7=158

х= 158*7

х=1106

1224-х: 6= 859

х:6= 1224- 859

х:6= 365

х= 365*6

х=2190

Answer 3

To solve the equation $1971 + \frac{x}{7} = 2129$, you can follow these steps:

Step 1: Subtract 1971 from both sides of the equation to isolate the variable term: $1971 + \frac{x}{7} - 1971 = 2129 - 1971$

Step 2: Simplify the equation: $\frac{x}{7} = 158$

Step 3: To solve for $x$, multiply both sides of the equation by 7 to cancel out the fraction: $x = 158 \times 7$

Step 4: Calculate the value of $x$: $x = 1106$

So, the value of $x$ that satisfies the equation is 1106.