Question

480÷4+ь*480÷(4+ь) (140+80)÷2*140+80÷2 500-240÷2+75*(500-240)÷2+75

Answer 1

ответ будет 2346

Пошаговое объяснение:

надеюсь помог

Answer 2

It looks like you've provided a series of mathematical expressions. Let's break down and calculate each one step by step:

1. $480÷4+ь*480÷(4+ь)$ Since the variable "ь" doesn't have a specific value mentioned, I'll leave it as a variable. If you meant a different variable or value, please provide that information.

2. $(140+80)÷2*140+80÷2$ $(140+80)÷2 = 220÷2 = 110$ $110*140 = 15400$ $80÷2 = 40$ $15400 + 40 = 15440$

3. $500-240÷2+75*(500-240)÷2+75$ $240÷2 = 120$ $500 - 120 = 380$ $75*(500-240) = 75*260 = 19500$ $19500÷2 = 9750$ $380 + 9750 + 75 = 10105$

If you have specific values for "ь" in the first expression, please provide them so I can calculate the result accurately.