Question

(5-x)²=(0.5a-b)²=(3x-2)²=(5m+3n)²=(0.4a-5b)²=​

Answer 1

(5-х)² = 25-10х+х²

(0,5а-b)² = 0,25a²-ab+b²

(3x-2)² = 9x²-12x+4

(5m+3n)² = 25m²+30mn+9n²

(0,4a-5b)² = 0,16a²-4ab+25b²

Answer 2

It seems like you want to solve the equations provided. Let's solve each equation step by step:

1. $(5-x)^2 = (0.5a-b)^2$

Expanding the left side: $25 - 10x + x^2 = 0.25a^2 - ab + b^2$

2. $(5-x)^2 = (3x-2)^2$

Expanding the left side: $25 - 10x + x^2 = 9x^2 - 12x + 4$

3. $(5-x)^2 = (5m+3n)^2$

Expanding the left side: $25 - 10x + x^2 = 25m^2 + 30mn + 9n^2$

4. $(5-x)^2 = (0.4a-5b)^2$

Expanding the left side: $25 - 10x + x^2 = 0.16a^2 - 4ab + 25b^2$

From the second equation, we have: $25 - 10x + x^2 = 9x^2 - 12x + 4$

Combining like terms and simplifying: $8x^2 - 2x - 21 = 0$

Solving this quadratic equation may give us the value(s) of $x$.

However, it's important to note that the equations given seem to be inconsistent or contradictory. If all these equations are meant to hold true simultaneously, they are conflicting because they don't share a common solution.

Please review the equations or provide more context so that I can assist you further.