Question

X^2+x-10<0 -x^2-5x-9<0 дискриминант

Answer 1

как я поняла вроде так надеюсь правильно

Answer 2

To find the solutions to the inequalities and determine their validity, we can start by solving the corresponding quadratic equations for each inequality. The quadratic equation is given by $ax^2 + bx + c = 0$, and its discriminant is $D = b^2 - 4ac$.

1. For $x^2 + x - 10 < 0$: Here, $a = 1$, $b = 1$, and $c = -10$. The discriminant is $D = b^2 - 4ac = 1^2 - 4(1)(-10) = 41$.

2. For $-x^2 - 5x - 9 < 0$: Here, $a = -1$, $b = -5$, and $c = -9$. The discriminant is $D = b^2 - 4ac = (-5)^2 - 4(-1)(-9) = 1$.

Now let's analyze the discriminants:

1. For $x^2 + x - 10 < 0$, the discriminant is positive ($D = 41$). This means the quadratic expression has two real and distinct solutions. The quadratic expression opens upwards (positive leading coefficient $a$), so it's negative between its two roots.

2. For $-x^2 - 5x - 9 < 0$, the discriminant is positive ($D = 1$). This means the quadratic expression has two real and distinct solutions. The quadratic expression opens downwards (negative leading coefficient $a$), so it's negative outside its two roots.

To find the exact solutions for each inequality, we need to solve the corresponding quadratic equations for $x$. However, since you are asking about the discriminants specifically, I've provided the discriminant analysis above. If you'd like, I can also help you find the solutions for the inequalities.