Question

1) 3(2x - 11)= -212) - 2(5-2x) =-143) |2x|+1=6​

Answer 1

1) 3(2х - 11) = -21

6х -66 = -21

6х = -21 + 66

6х = -81

х = -81/6

х = - 13,5

2) -2(5-2х)= -14

-10 +4х = -14

4х = -14 +10

4х = -4

х= -4 / 4

х= -1

3) |2х| +1 = 6

тк 2х заключено под знаком модуля то у нас появляется два варианта решения, где

если 2х>0, то

2х +1 =6

2х = 6-1

2х = 5

х = 5/2

х = 2,5

если 2х<0, то

-2х+1 = 6

-2х =6-1

-2х = 5

х= 5/(-2)

х=-2,5

Answer 2

Let's solve the equations one by one:

1. 3(2x - 11) = -21

First, distribute the 3 to the terms inside the parentheses:

6x - 33 = -21

Next, isolate the variable by adding 33 to both sides:

6x = -21 + 33 6x = 12

Finally, divide both sides by 6 to solve for x:

x = 12/6 x = 2

So the solution to the equation is x = 2.

2. -2(5 - 2x) = -14

First, distribute the -2 to the terms inside the parentheses:

-10 + 4x = -14

Next, isolate the variable by adding 10 to both sides:

4x = -14 + 10 4x = -4

Finally, divide both sides by 4 to solve for x:

x = -4/4 x = -1

So the solution to the equation is x = -1.

3. |2x| + 1 = 6

To solve this equation, we need to consider two cases: one when 2x is positive and one when 2x is negative.

Case 1: 2x is positive

In this case, we have:

2x + 1 = 6

Subtract 1 from both sides:

2x = 6 - 1 2x = 5

Divide both sides by 2:

x = 5/2 x = 2.5

Case 2: 2x is negative

In this case, we have:

-(2x) + 1 = 6

Subtract 1 from both sides:

-2x = 6 - 1 -2x = 5

Divide both sides by -2:

x = 5/(-2) x = -2.5

So the solutions to the equation are x = 2.5 and x = -2.5.