Question

|1-0,25x|+(2x-8)⁶=0​

Answer 1

Ответ:

|1-0.25х|+(2х-8)^4 =0;

^ значок степени

0,25·|4-х|+16(х-4)^4 =0

0,25·|х-4|+16·|х-4|^4 =0

|х-4|+64·|х-4|^4 =0

|х-4|(1+64·|х-4|³) =0

|х-4|=0

х-4=0

х1=4

1+64·|х-4|³ =0

|х-4|³ =-1/64<0 решений нет

Ответ: 4

Пошаговое объяснение:

Answer 2

The equation you've provided is nonlinear due to the presence of the absolute value and the sixth power term. To solve for the value(s) of "x," you'll need to handle each part of the equation separately. Let's break down the equation step by step and solve it:

1. |1 - 0.25x| + (2x - 8)^6 = 0

First, let's deal with the absolute value term:

2. |1 - 0.25x| = - (2x - 8)^6

Absolute value expressions can never be negative, so the left-hand side (LHS) of the equation can never equal a negative value on the right-hand side (RHS). This means that there are no real solutions for this equation.

However, if you made an error in copying the equation or if there's a typo, please correct it and I'll be happy to help you solve the corrected equation.