Question

-(25+а-4в)= 11(-в-5-6а)= -9(8+х-4у) = 18(-а-в+с)= -(5-а+54в)= 100(в+9-3а)=​

Answer 1

Ответ:

Что именно сделать нужно? Скажи пожалуйста.....

Answer 2

Let's solve the system of equations step by step:

Equation 1: -(25 + а - 4в) = 11(-в - 5 - 6а)

To simplify, distribute the -11 on the right side of the equation: -25 - а + 4в = -11(-в - 5 - 6а)

Expand the right side: -25 - а + 4в = 11в + 55 + 66а

Rearrange the terms: -а - 4в + 11в + 66а = 55 + 25

Combine like terms: 65а - 7в = 80 Equation A

Equation 2: -9(8 + х - 4у) = 18(-а - в + с)

Expand both sides: -72 - 9х + 36у = -18а - 18в + 18с

Rearrange the terms: -9х + 36у + 18а + 18в - 18с = 72 Equation B

Equation 3: -(5 - а + 54в) = 100(в + 9 - 3а)

Distribute the 100 on the right side: -5 + а - 54в = 100в + 900 - 300а

Rearrange the terms: а + 300а + 54в + 100в = 900 + 5

Combine like terms: 301а + 154в = 905 Equation C

Equation 4: 100(в + 9 - 3а) = 18(-а - в + с)

Distribute the 100 on the left side: 100в + 900 - 300а = -18а - 18в + 18с

Rearrange the terms: 300а + 18а + 18в + 100в - 18с = 900 - 900

Combine like terms: 318а + 118в - 18с = 0 Equation D

Now we have the following system of equations: Equation A: 65а - 7в = 80 Equation B: -9х + 36у + 18а + 18в - 18с = 72 Equation C: 301а + 154в = 905 Equation D: 318а + 118в - 18с = 0

To solve this system of equations, we can use any method like substitution, elimination, or matrix methods. Which method would you like to use?