Question

1)3,2⋅(x+0,84)=8,32 2)0,084:(6,2_x)=1,2

Answer 1

Ответ:х=4, х=3,2

Пошаговое объяснение:

)3,2⋅(x+0,84)=8,32

2)0,084:(6,2_x)=1,2

Answer 2

It seems like you've provided two equations with variables. You'd like to solve for the variable $x$ in each equation. Let's solve them step by step:

Equation 1: $3.2 \cdot (x + 0.84) = 8.32$

Step 1: Distribute the 3.2 on the left side of the equation: $3.2x + 3.2 \cdot 0.84 = 8.32$

Step 2: Multiply 3.2 and 0.84: $3.2x + 2.688 = 8.32$

Step 3: Subtract 2.688 from both sides of the equation: $3.2x = 8.32 - 2.688$ $3.2x = 5.632$

Step 4: Divide both sides by 3.2 to solve for $x$: $x = \frac{5.632}{3.2}$ $x = 1.76$

So, the solution for equation 1 is $x = 1.76$.

Equation 2: $0.084 : (6.2x) = 1.2$

Step 1: Divide both sides of the equation by 0.084: $\frac{0.084}{6.2x} = 1.2$

Step 2: Multiply both sides by $6.2x$: $6.2x \cdot \frac{0.084}{6.2x} = 1.2 \cdot 6.2x$ $0.084 = 7.44x$

Step 3: Divide both sides by 7.44 to solve for $x$: $x = \frac{0.084}{7.44}$ $x = 0.0113$

So, the solution for equation 2 is $x = 0.0113$.

To summarize:

1. $x = 1.76$
2. $x = 0.0113$