Question

-8(x-12)(x+28)=0 X= X=

Answer 1

Пошаговое объяснение:

8(х-12)(х+28)=0

(х-12)(х+28)=0

Х-12=0

Х+28=0

Х1=12

Х2=-28

Answer 2

To solve the quadratic equation -8(x - 12)(x + 28) = 0, you need to set each factor equal to zero and solve for x:

1. Setting x - 12 = 0: x - 12 = 0 x = 12

2. Setting x + 28 = 0: x + 28 = 0 x = -28

So, the solutions for the equation -8(x - 12)(x + 28) = 0 are:

• x = 12
• x = -28