Question

1)2/7x-3/14y-1/7=02)x+5y-24=0​

Answer 1

Ответ:

Пошаговое объяснение:

Если это системное уравнение то решать так:

4х-3у-2=0

х=24-5у

4(24-5у)-3у-2=0

х=24-5у

96-20у-3у-2=0

х=24-5у

94=23у

х=24-5у

у=4 2/23

х=24-5×94/23

у=4 2/23

х=24-20 10/23

у=4 2/23

х=3 13/23

Answer 2

To solve the system of equations:

1. 2/7x - 3/14y - 1/7 = 0
2. x + 5y - 24 = 0

We can use the method of substitution or elimination. Let's use the method of substitution in this case.

From equation 2, we can express x in terms of y:

x = 24 - 5y

Now, substitute this expression for x in equation 1:

2/7(24 - 5y) - 3/14y - 1/7 = 0

Multiplying through by the least common denominator, which is 14, to eliminate fractions:

(4/2)(24 - 5y) - (3/1)y - 2 = 0

Simplifying:

(48 - 10y) - 3y - 2 = 0 48 - 10y - 3y - 2 = 0 48 - 13y - 2 = 0 46 - 13y = 0 -13y = -46 y = (-46)/(-13) y = 46/13 y = 3.54 (rounded to two decimal places)

Now, substitute the value of y back into equation 2 to find x:

x + 5(3.54) - 24 = 0 x + 17.7 - 24 = 0 x - 6.3 = 0 x = 6.3

Therefore, the solution to the system of equations is x = 6.3 and y = 3.54.