Question

4x > 14; 7x > 40 7/9

Answer 1

Ответ:

1) х больше 3,5. 2)х больше 5 52/63

Пошаговое объяснение:

1) Делим обе части на 4: 4х/4 больше 14/4

х больше 14/4

Сокращаем на 2: х больше 7/2

Переводим в десятичную: х больше 3,5

2) Представим смешанную дробь в виде неправильной: 7х больше 367/9

Делим обе части на 7: х больше 367/63

Переводим в смешанную дробь: х больше 5 52/63

Answer 2

To solve the inequalities, let's start with the first one:

1. $4x > 14$

Divide both sides by 4 to solve for $x$:

$x > \frac{14}{4}$

$x > \frac{7}{2}$

Now, let's move on to the second inequality:

2. $7x > \frac{40}{9}$

Divide both sides by 7:

$x > \frac{40}{9 \times 7}$

$x > \frac{40}{63}$

So, the solution for the second inequality is $x > \frac{40}{63}$.

To find the combined solution for both inequalities, we need to find the range of values that satisfy both conditions. Since both inequalities require $x$ to be greater than certain values, we'll take the larger of the two values:

$x > \max\left(\frac{7}{2}, \frac{40}{63}\right)$

Comparing these two values, we see that $\frac{7}{2}$ is larger than $\frac{40}{63}$. Therefore, the combined solution is:

$x > \frac{7}{2}$

In interval notation, the solution is $\left(\frac{7}{2}, +\infty\right)$. This represents all values of $x$ that are greater than $\frac{7}{2}$.