Question

1)3 3/14 -3 2/3 y = 1 8/21 2) (7/12 + 1/9у) :3 2/3 = 1/6 пж дайте ответ

Answer 1

$\frac{45}{14} - \frac{11 y}{3} =\frac{29}{21} \\\\ \frac{135}{42} -\frac{44 y}{42} =\frac{58}{42} \\\\\frac{135-58}{42} =\frac{44 y}{42}\\\\ \frac{77}{42} =\frac{44 y}{42} \\77=44 y\\7=4 y\\ y=\frac{7}{4}$

$(\frac{7}{12} + \frac{ y}{9}) / \frac{11}{3} =\frac{1}{6}\\\\(\frac{21}{36} +\frac{4 y}{36})/\frac{11}{3} =\frac{1}{6} \\\\\frac{21+4y}{36} *\frac{3}{11} =\frac{231+44y}{12} =\frac{1}{6} \\\frac{231+44y}{12} -\frac{1}{6}=0\frac{231+44y}{12} -\frac{2}{12}=0\\\frac{229+44y}{12}=0\\\\229+44y=0\\44y=-229\\y=\frac{-229}{44}$

Answer 2

1. To solve the equation $3 \frac{3}{14} - 3 \frac{2}{3} y = 1 \frac{8}{21},$ follow these steps:

Step 1: Convert all the mixed numbers to improper fractions. $3 \frac{3}{14} = \frac{3 \times 14 + 3}{14} = \frac{45}{14},$ $3 \frac{2}{3} = \frac{3 \times 3 + 2}{3} = \frac{11}{3},$ $1 \frac{8}{21} = \frac{1 \times 21 + 8}{21} = \frac{29}{21}.$

Step 2: Substitute the fractions into the equation: $\frac{45}{14} - \frac{11}{3} y = \frac{29}{21}.$

Step 3: To solve for $y,$ isolate $y$ on one side of the equation: $\frac{45}{14} - \frac{11}{3} y = \frac{29}{21}.$ Multiply all terms by the least common multiple (LCM) of the denominators, which is $14 \times 3 \times 21 = 882:$ $882 \cdot \frac{45}{14} - 882 \cdot \frac{11}{3} y = 882 \cdot \frac{29}{21},$ $2835 - 343y = 1162.$ Now, subtract $2835$ from both sides: $-343y = -1673.$ Finally, divide both sides by $-343$ to solve for $y:$ $y = \frac{-1673}{-343} = \frac{1673}{343}.$

So, the solution to the equation is $y = \frac{1673}{343}.$

2. To solve the equation $\left(\frac{7}{12} + \frac{1}{9}y\right) : 3 \frac{2}{3} = \frac{1}{6},$ follow these steps:

Step 1: Convert the mixed number to an improper fraction. $3 \frac{2}{3} = \frac{3 \times 3 + 2}{3} = \frac{11}{3}.$

Step 2: Substitute the fractions into the equation: $\left(\frac{7}{12} + \frac{1}{9}y\right) : \frac{11}{3} = \frac{1}{6}.$

Step 3: To solve for $y,$ isolate $y$ on one side of the equation: $\left(\frac{7}{12} + \frac{1}{9}y\right) : \frac{11}{3} = \frac{1}{6}.$ Multiply both sides by $\frac{11}{3}:$ $\frac{11}{3} \cdot \left(\frac{7}{12} + \frac{1}{9}y\right) = \frac{11}{3} \cdot \frac{1}{6},$