Question

((3 1/3+5 7/9)*2 1/4-1 1/15*(3 5/6-7/12+9 7/9))*16/39==

Answer 1

Ответ:

вот ответ проверял в онлайн канкуяторе

Answer 2

ппц,

1552

- -----------

405

так кажется

Answer 3

Let's break down the equation step by step to solve it:

1. Calculate the values in the parentheses:

   • $3 \frac{1}{3} + 5 \frac{7}{9} = \frac{10}{3} + \frac{52}{9} = \frac{30}{9} + \frac{52}{9} = \frac{82}{9}$
   • $3 \frac{5}{6} - \frac{7}{12} + 9 \frac{7}{9} = \frac{23}{6} - \frac{7}{12} + \frac{80}{9} = \frac{46}{12} - \frac{7}{12} + \frac{80}{9} = \frac{119}{12}$
   • $2 \frac{1}{4} = \frac{9}{4}$
   • $1 \frac{1}{15} = \frac{16}{15}$

2. Substitute the calculated values back into the equation: $\left(\frac{82}{9} \times \frac{9}{4} - \frac{16}{15} \times \frac{119}{12}\right) \times \frac{16}{39}$

3. Perform multiplications and subtractions:

   • $\frac{82}{9} \times \frac{9}{4} = \frac{82}{4} = \frac{41}{2}$
   • $\frac{16}{15} \times \frac{119}{12} = \frac{1904}{180} = \frac{952}{90} = \frac{476}{45}$

   So the equation becomes: $\left(\frac{41}{2} - \frac{476}{45}\right) \times \frac{16}{39}$

4. Subtract and multiply:

   • $\frac{41}{2} - \frac{476}{45} = \frac{205}{10} - \frac{476}{45} = \frac{205 \times 9}{10 \times 9} - \frac{476}{45} = \frac{1845}{90} - \frac{476}{45} = \frac{1845 - 952}{90} = \frac{893}{90}$
   • $\frac{893}{90} \times \frac{16}{39} = \frac{893 \times 16}{90 \times 39} = \frac{14288}{3510}$