Question

3\28+15\28-11\28 1-17\20 3 7\23-1 4\23 5 3\8-3 5\8

Answer 1

Ответ:

Решение и ответы ниже

Пошаговое объяснение:

3\28+15\28-11\28=$\frac{3+15-11}{28}=\frac{7}{28} =\frac{1}{4}$

1-17\20=$\frac{20}{20} -\frac{17}{20} =\frac{3}{20}$

3 7\23-1 4\23=$\frac{76}{23} -\frac{27}{23} =\frac{49}{23} =2\frac{3}{23}$

5 3\8-3 5\8=$\frac{43}{8} -\frac{29}{8} =\frac{14}{8} =1\frac{6}{8} =1\frac{3}{4}$

Answer 2

It seems like you've provided a series of mathematical expressions. Let's break them down step by step:

1. $\frac{3}{28} + \frac{15}{28} - \frac{11}{28}$ This expression involves adding three fractions with a common denominator of 28: $\frac{3 + 15 - 11}{28} = \frac{7}{28} = \frac{1}{4}$

2. $1 - \frac{17}{20}$ Subtracting a fraction from a whole number: $\frac{20}{20} - \frac{17}{20} = \frac{3}{20}$

3. $\frac{7}{23} - 1$ Subtracting a whole number from a fraction: $\frac{7}{23} - \frac{23}{23} = -\frac{16}{23}$

4. $\frac{4}{23} + 5$ Adding a whole number to a fraction: $\frac{4}{23} + \frac{115}{23} = \frac{119}{23}$

5. $\frac{3}{8} - \frac{3}{8}$ Subtracting fractions with the same denominator: $\frac{0}{8} = 0$

6. $5 - \frac{3}{8}$ Subtracting a fraction from a whole number: $\frac{40}{8} - \frac{3}{8} = \frac{37}{8}$

So, the simplified results for each expression are:

1. $\frac{1}{4}$
2. $\frac{3}{20}$
3. $-\frac{16}{23}$
4. $\frac{119}{23}$
5. $0$
6. $\frac{37}{8}$