Question

2х + 5 у - 16 =0 -2 х - 7 у +20 =0​

Answer 1

Відповідь:

Покрокове пояснення:

Answer 2

The given system of linear equations is:

1. $2x + 5y - 16 = 0$
2. $-2x - 7y + 20 = 0$

To solve this system of equations, we can use the method of substitution or elimination. I'll use the elimination method in this case.

First, let's multiply the second equation by 1 to make it easier to eliminate one of the variables:

2. $2x + 7y - 20 = 0$

Now, let's add the first equation to the second equation to eliminate $x$:

$(2x + 5y - 16) + (2x + 7y - 20) = 0 + 0$

Simplifying the left side:

$4x + 12y - 36 = 0$

Now, let's divide the entire equation by 4 to simplify it further:

$x + 3y - 9 = 0$

Now we have:

1. $x + 3y - 9 = 0$
2. $2x + 7y - 20 = 0$

Next, let's solve equation 1 for $x$:

$x = 9 - 3y$

Now, substitute this value of $x$ into equation 2:

$2(9 - 3y) + 7y - 20 = 0$

Simplify the equation:

$18 - 6y + 7y - 20 = 0$

Combine the $y$ terms:

$y - 2 = 0$

Now solve for $y$:

$y = 2$

Substitute the value of $y$ back into the equation $x = 9 - 3y$:

$x = 9 - 3(2) = 9 - 6 = 3$

So, the solution to the system of equations is $x = 3$ and $y = 2$.