Question

1)cos3=−1/2 2)sin6=− 1/2

Answer 1

Ответ:

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Answer 2

It seems like you're looking for solutions to trigonometric equations. I can help you with that!

1. To solve the equation cos(3θ) = -1/2, you need to find the values of θ that satisfy this equation. One way to approach this is by using the inverse cosine function (arccos) to find the angles that have a cosine value of -1/2. Remember that cosine is negative in the second and third quadrants.

Using the unit circle and considering the second and third quadrants, you can find two angles that satisfy the equation: θ = π + arccos(-1/2) θ = 2π - arccos(-1/2)

2. Similarly, to solve the equation sin(6θ) = -1/2, you'll need to use the inverse sine function (arcsin) to find the angles that have a sine value of -1/2. Sine is negative in the third and fourth quadrants.

Again, using the unit circle and considering the third and fourth quadrants, you can find two angles that satisfy the equation: θ = π - arcsin(-1/2) θ = 2π + arcsin(-1/2)

Please note that these values of θ might need to be adjusted to fit within a specific range, such as [0, 2π) or [0, 360°), depending on the context of the problem you're solving.