Question

2sin 120°+ cos 240° + 3tg 135°.

Answer 1

Ответ:

$\sqrt{3}-\dfrac{7}{2}$

Пошаговое объяснение:

2sin 120°+ cos 240° + 3tg 135°=$\sqrt{3}-\dfrac{1}{2}-3=\sqrt{3}-\dfrac{7}{2}$

Answer 2

Let's break down the given trigonometric expression step by step:

1. 2sin 120°: The sine function at 120° is √3/2. So, 2sin 120° = 2 * √3/2 = √3.

2. cos 240°: The cosine function at 240° is -1/2. So, cos 240° = -1/2.

3. 3tg 135°: The tangent function at 135° is -1. So, 3tg 135° = 3 * (-1) = -3.

Now, add up the values:

√3 + (-1/2) - 3 = √3 - 1/2 - 3

To simplify further:

√3 - 7/2

So, the value of the expression 2sin 120° + cos 240° + 3tg 135° is approximately equal to √3 - 7/2.