Question

F(x)=cos√x в точці x0= n^2/4​

Answer 1

Ответ:

Пошаговое объяснение:

f`(x)=cosx-x*sinx

f`(π)=cosπ-π*sinπ=-1-π*0=-1

Answer 2

To find the value of the function $F(x) = \cos(\sqrt{x})$ at the point $x_0 = \frac{n^2}{4}$, where $n$ is a constant, you simply substitute $x_0$ into the function and evaluate it. Here's how you can do it:

Given $x_0 = \frac{n^2}{4}$, you can substitute this value into the function:

$F(x_0) = \cos(\sqrt{x_0}) = \cos(\sqrt{\frac{n^2}{4}}) = \cos\left(\frac{n}{2}\right)$

So, the value of the function $F(x) = \cos(\sqrt{x})$ at the point $x_0 = \frac{n^2}{4}$ is $\cos\left(\frac{n}{2}\right)$.