Question

1)log5(4+x)=3 2)2^8 умножить на 25^8:50^6

Answer 1

Ответ:   121;  2500

Пошаговое объяснение:1)  по определению логарифма 4+х=5^3, 4+x=125, x=121                                                                                                                                 2) по свойству степени  2^8*25^8=(2*25)^8=50^8                                                        3)по свойству деления степеней с одним основанием:50^8:50^6=

=50^2=2500

Answer 2

Sure, I can help you with that!

1. To solve the equation log₅(4+x) = 3 for x:

First, we'll use the property of logarithms that states if logₐ(b) = c, then a^c = b. In this case, we have:

log₅(4+x) = 3

This means that 5^3 = 4+x.

Solving for x:

5^3 = 125 4+x = 125

Subtracting 4 from both sides:

x = 125 - 4 x = 121

So, the solution for the equation is x = 121.

2. To calculate 2^8 multiplied by 25^8 and then divided by 50^6:

2^8 * 25^8 / 50^6

First, let's simplify the terms:

2^8 = 256 25^8 = 25^(2 * 4) = (25^2)^4 = 625^4 = 390,625 50^6 = (2 * 25)^6 = 2^6 * 25^6 = 64 * 15,625 = 1,000,000

Now, substitute these values back into the expression:

(256 * 390,625) / 1,000,000

Calculating the multiplication:

99,840,000 / 1,000,000 = 99.84

So, 2^8 * 25^8 / 50^6 is equal to approximately 99.84.