Question

5005-2002=35×143-143×4; 5005-35×143=2002-143×14;5(1001-7×143)=2(1001-7×143);5=2(!)​

Answer 1

Ответ:

Я не знаю, что нужно сделать, ты не написал. Могу лишь предположить, что нужно написать где верные равенства. Верные 2 и 3

Answer 2

It looks like you're trying to show some equations and simplify them step by step. Let's break down each step:

1. 5005 - 2002 = 35 × 143 - 143 × 4

   This equation is comparing the difference between 5005 and 2002 with the difference between the products of 35 and 143, and 143 and 4.

2. 5005 - 35 × 143 = 2002 - 143 × 14

   This equation involves subtracting the product of 35 and 143 from 5005 and comparing it with the difference between 2002 and the product of 143 and 14.

3. 5(1001 - 7 × 143) = 2(1001 - 7 × 143)

   Here, both sides of the equation are being multiplied by a common factor of 5 and 2 respectively. The expression within the parentheses on both sides is also the same: $1001 - 7 \times 143$.

4. 5 = 2(!)

   It seems you've simplified the equation further, suggesting that 5 is equal to 2 factorial (!).

However, there seems to be an issue with these equations. The step where you equate $5$ to $2(!)$ doesn't seem to be mathematically accurate. Factorial (!) is a mathematical operation where $n!$ represents the product of all positive integers from $1$ to $n$. The factorial of $2$ is $2! = 2 \times 1 = 2$, not $5$.

If you could provide more context or clarify your intentions, I'd be happy to help you understand or correct any mistakes in the equations!