Question

X2-m(n+1)x+m+n+1 = 0​

Answer 1

Ответ:

х2-m (n+1)x+m+n+1 = 0

ответ выше

Answer 2

It seems like you've provided a quadratic equation: $x^2 - m(n+1)x + m+n+1 = 0$. This equation is in the form $ax^2 + bx + c = 0$, where $a = 1$, $b = -m(n+1)$, and $c = m+n+1$.

To solve this quadratic equation for $x$, you can use the quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Plugging in the values for $a$, $b$, and $c$, the formula becomes:

$x = \frac{m(n+1) \pm \sqrt{m^2(n+1)^2 - 4(m+n+1)}}{2}$

You can simplify this further and then compute the two possible values of $x$ (since quadratic equations typically have two solutions unless the discriminant $b^2 - 4ac$ is negative, in which case there are no real solutions). Just be sure to pay attention to the specific values of $m$ and $n$ when performing the calculations.