Question

Y = х² - 8x + 18; у= -2x +18​

Answer 1

Ответ:

вот ответ

рлплдашчешвршащгп

Answer 2

It seems like you've provided two equations:

1. $Y = x^2 - 8x + 18$
2. $Y = -2x + 18$

It appears that both equations are representing the variable $Y$ in terms of $x$. However, the second equation uses $y$ instead of $Y$, which might be a typo.

If you're looking to solve for the values of $x$ and $Y$ (or $y$) that satisfy both equations simultaneously, you need to find the points of intersection. This means finding the values of $x$ where the two equations yield the same $Y$ (or $y$) value. In other words, you're looking for the values of $x$ where the two equations are equal:

$x^2 - 8x + 18 = -2x + 18$

Let's solve this equation:

Subtracting $-2x + 18$ from both sides:

$x^2 - 8x = 0$

Factoring out $x$:

$x(x - 8) = 0$

Setting each factor equal to zero:

$x = 0$ or $x - 8 = 0$

So, the solutions for $x$ are $x = 0$ and $x = 8$.

Now, let's find the corresponding $Y$ (or $y$) values using the given equations:

1. For $x = 0$, $Y = 0^2 - 8 \cdot 0 + 18 = 18$
2. For $x = 8$, $Y = 8^2 - 8 \cdot 8 + 18 = 18$

Both solutions yield the same $Y$ (or $y$) value of 18.

So, the points of intersection for these equations are (0, 18) and (8, 18). This means that these two equations intersect at the points where $x = 0$ and $Y = 18$, as well as where $x = 8$ and $Y = 18$.