Question

3x^2+x=

Answer 1

Решение приложено...

Answer 2

It looks like you've provided an equation: 3x^2 + x = 0. This is a quadratic equation, which is a second-degree polynomial equation. To solve for the value(s) of x that satisfy this equation, we can factor it or use the quadratic formula.

Let's solve it using the quadratic formula:

The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b^2 - 4ac)) / 2a

In your equation, a = 3, b = 1, and c = 0:

x = (-(1) ± √((1)^2 - 4(3)(0))) / (2(3)) x = (-1 ± √(1)) / 6 x = (-1 ± 1) / 6

This gives two possible solutions:

1. x = (−1 + 1) / 6 = 0 / 6 = 0
2. x = (−1 - 1) / 6 = -2 / 6 = -1/3

So, the solutions for the equation 3x^2 + x = 0 are x = 0 and x = -1/3.