Question

find three consecutive odd integers such that the sum of the first, two times the second, and three times the third is 70.

Answer 1

Ответ:

9, 11, 13

Пошаговое объяснение:

x - first odd integer

(x+2) and (x+4) - next two consecutive odd integers

x + 2(x+2) + 3(x+4) = 70

6x +4 + 12 = 70

6x = 54

x = 9

Answer 2

Let's represent the three consecutive odd integers as x, x + 2, and x + 4.

According to the problem, the sum of the first, two times the second, and three times the third is 70. We can write this as an equation:

x + 2(x + 2) + 3(x + 4) = 70

Now, let's solve this equation to find the value of x:

x + 2x + 4 + 3x + 12 = 70 6x + 16 = 70 6x = 70 - 16 6x = 54 x = 54/6 x = 9

So, the first odd integer is 9, the second is 11 (9 + 2), and the third is 13 (9 + 4).