Question

15/20 ∶5/15= -15/(20 )* 5/15=(15*5)/(20*15)=(сокращаем)=-1/4 1)11/120 ∶(-121/12)=?2)-250/400 ∶(-25/20)=?3)11/12,2 ∶11/2=?4)6/81:3/9=?5)555/444:4/5=?​

Answer 1

Ответ:

Пошаговое объяснение:$\frac{15}{20} : \frac{5}{15} = \frac{15*15}{20*5} = \frac{3*3}{4} = \frac{9}{4} =2 \frac{1}{4}$ =2,25

$\frac{11}{120} : -\frac{121}{12} =- \frac{11*12}{120*121} =- \frac{1}{110}$

$-\frac{250}{400} : -\frac{25}{20} = \frac{250*20}{400*25} = \frac{10}{20} = \frac{1}{2}$ = 0,5

$\frac{11}{12,2} : \frac{11}{2} = \frac{11*2}{12,2*11} = \frac{1}{6,1}$

$\frac{6}{81} : \frac{3}{9} = \frac{6*9}{81*3} = \frac{2}{9}$

$\frac{555}{444} : \frac{4}{5} = \frac{555*5}{444*4} = \frac{25}{16} = 1\frac{9}{16}$

Answer 2

Let's solve each of these division problems step by step:

1. $\frac{11}{120} \div \left(\frac{-121}{12}\right)$

To divide fractions, you can multiply the first fraction by the reciprocal of the second fraction (flipping the second fraction upside down):

$\frac{11}{120} \div \left(\frac{-121}{12}\right) = \frac{11}{120} \cdot \frac{-12}{-121}$

Now, simplify the fraction:

$\frac{11}{120} \cdot \frac{-12}{-121} = \frac{11 \cdot (-12)}{120 \cdot (-121)}$

Simplify further if possible:

$\frac{-132}{-14520}$

Now, let's simplify this fraction by dividing both the numerator and denominator by their greatest common divisor, which is 4:

$\frac{-132 \div 4}{-14520 \div 4} = \frac{-33}{-3630}$

Now, simplify further by dividing both the numerator and denominator by 33:

$\frac{-33 \div 33}{-3630 \div 33} = \frac{-1}{-110}$

Finally, since the numerator and denominator are both negative, the fraction simplifies to a positive value:

$\frac{-1}{-110} = \frac{1}{110}$

So, $\frac{11}{120} \div \left(\frac{-121}{12}\right) = \frac{1}{110}$.

2. $\frac{-250}{400} \div \left(\frac{-25}{20}\right)$

Let's simplify this step by step. First, simplify the fractions inside the division:

$\frac{-250}{400} \div \frac{-25}{20}$

Now, simplify the fractions:

$\frac{-5}{8} \div \frac{-5}{4}$

To divide fractions, multiply by the reciprocal:

$\frac{-5}{8} \cdot \frac{4}{-5}$

Now, simplify the fraction:

$\frac{(-5) \cdot 4}{8 \cdot (-5)}$

Simplify further if possible:

$\frac{-20}{-40}$

Now, let's simplify this fraction by dividing both the numerator and denominator by their greatest common divisor, which is 20:

$\frac{-20 \div 20}{-40 \div 20} = \frac{-1}{-2}$

Finally, since both the numerator and denominator are negative, the fraction simplifies to a positive value:

$\frac{-1}{-2} = \frac{1}{2}$

So, $\frac{-250}{400} \div \left(\frac{-25}{20}\right) = \frac{1}{2}$.

3. $\frac{11}{12.2} \div \frac{11}{2}$

First, simplify the fractions inside the division:

$\frac{11}{12.2} \div \frac{11}{2}$

Now, divide the fractions by multiplying by the reciprocal:

$\frac{11}{12.2} \cdot \frac{2}{11}$

Now, simplify the fraction:

$\frac{11 \cdot 2}{12.2 \cdot 11}$

Simplify further if possible:

$\frac{22}{122}$