Question

1. a) 35 + (-11); 6) -22 + (-15); B) 25 + (-39); r) -33 + (-42).2. a) 35 - (-11); 6) -22 - (-15);B) 25 - (-39); r) -33 - (-42)3. a) 42 + (-16); 6) -37 -(-62);B) -17 + (-52); r) -39 - 35.4. a) 422 + (-26)-(-36); 6) -465 - (-47) + (-27);B) -125 + 125 - (-5); r) -38 - (-38) -4.5*. -53 + (-52) + (-51) + ... +53 +54 +55.​

Answer 1

Пошаговое объяснение:

1. a) 35 + (-11)=24

6) -22 + (-15)=-37

B) 25 + (-39)=-14

r) -33 + (-42)=-75

2. a) 35 - (-11)=46

6) -22 - (-15)=-7

B) 25 - (-39)=64

r) -33 - (-42)=9

3. a) 42 + (-16)=26

6) -37 -(-62)=25

B) -17 + (-52)=-69

r) -39 - 35=-74

4. a) 422 + (-26)-(-36)=432

6) -465 - (-47) + (-27)=485

B) -125 + 125 - (-5)=5

r) -38 - (-38) -4=-4

5*. -53 + (-52) + (-51) + ... +53 +54 +55=109 (все числа, кроме 54 и 55 имеют противоположное значение и взаимноуничтожаются и остаётся лишь 54+55)

Answer 2

Let's solve each of the expressions step by step:

1. a) 35 + (-11) = 24 6) -22 + (-15) = -37 B) 25 + (-39) = -14 r) -33 + (-42) = -75

2. a) 35 - (-11) = 35 + 11 = 46 6) -22 - (-15) = -22 + 15 = -7 B) 25 - (-39) = 25 + 39 = 64 r) -33 - (-42) = -33 + 42 = 9

3. a) 42 + (-16) = 26 6) -37 - (-62) = -37 + 62 = 25 B) -17 + (-52) = -69 r) -39 - 35 = -74

4. a) 422 + (-26) - (-36) = 422 + (-26) + 36 = 432 6) -465 - (-47) + (-27) = -465 + 47 + (-27) = -445 B) -125 + 125 - (-5) = -125 + 125 + 5 = 5 r) -38 - (-38) - 4 = -38 + 38 - 4 = -4

5*. To find the sum of the series -53 + (-52) + (-51) + ... + 53 + 54 + 55, we can notice a pattern. The series consists of consecutive integers from -53 to 55. There are 109 terms in total (from -53 to 55).

To find the sum, you can use the formula for the sum of an arithmetic series: Sum = (n/2) * [2a + (n - 1) * d]

where: n = 109 (number of terms) a = -53 (first term) d = 1 (common difference between terms)

Sum = (109/2) * [2 * (-53) + (109 - 1) * 1] Sum = (109/2) * [-106 + 108] Sum = (109/2) * 2 Sum = 109

So, the sum of the series is 109.