Question

1) (2x-1)(2x+1)=x(2x+3);​

Answer 1

____________________

Answer 2

Ответ:

Пошаговое объяснение:

(2х)^2 -1^2=2х^2+3х

4х^-1 -2х^2 -3х=0

2х^2-3х-1=0

D=(-3)^2-4•2•(-1)=9+8= 17

Подкорнем D=Подкорнем 17

Х1=(3+подк 17)/4

Х2=(3-подк 17)/4

Answer 3

To solve the given equation, let's start by expanding both sides:

(2x - 1)(2x + 1) = x(2x + 3)

Expanding the left side using the FOIL method (First, Outer, Inner, Last), we get:

4x^2 - 1 = 2x^2 + 3x

Now, let's simplify the equation by combining like terms:

4x^2 - 1 - 2x^2 - 3x = 0

Combining the x^2 terms and the constant terms, we have:

(4x^2 - 2x^2) + (-1 - 3x) = 0

Simplifying further:

2x^2 - 3x - 1 = 0

Now, we have a quadratic equation. To solve it, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

For our equation, a = 2, b = -3, and c = -1. Substituting these values into the quadratic formula, we get:

x = (3 ± √((-3)^2 - 4 * 2 * -1)) / (2 * 2)

Simplifying inside the square root:

x = (3 ± √(9 + 8)) / 4 x = (3 ± √17) / 4

Therefore, the solutions to the equation (2x - 1)(2x + 1) = x(2x + 3) are:

x = (3 + √17) / 4 x = (3 - √17) / 4