Question

A=9b c=d:6 ab=54 a=b9 54a=b c=6:d

Answer 1

Ответ:

54a⁶b⁹/c¹² * -c²⁰/12a⁴b¹⁵=

-54a⁶b⁹c²⁰/12a⁴b¹⁵c¹²=

-4.5a²b⁻⁶c⁸

            По действиям:  -54/12=-4.5

                                         a⁶/a⁴=a⁽⁶⁻⁴⁾=a²

                                          b⁹/b¹⁵=b⁽⁹⁻¹⁵⁾=b⁻⁶

                                           c²⁰/c¹²=c⁽²⁰⁻¹²⁾=c⁸

Пошаговое объяснение:

Answer 2

It seems like you have provided a series of equations with variables and values. Let's try to solve these equations:

1. A = 9b
2. c = d:6
3. ab = 54
4. a = b9
5. 54a = b
6. c = 6:d

Let's break these down one by one:

From equation 3, ab = 54, we can substitute this into equation 5: a = 54/b

Now, let's substitute this value of "a" into equation 4: 54/b = b9

Solve for b: 54 = b^2 * 9 b^2 = 54 / 9 b^2 = 6 b = ±√6

Now that we have the value of "b," we can find the value of "a" using equation 3: ab = 54 a * (±√6) = 54

If we take the positive square root of 6: a * √6 = 54 a = 54 / √6

Now, let's simplify "a" further by rationalizing the denominator (multiplying the numerator and denominator by √6): a = (54 / √6) * (√6 / √6) a = (54√6) / 6 a = 9√6

So, we have found the values of "a" and "b": a = 9√6 b = ±√6

Now, let's look at the remaining equations:

1. A = 9b
2. c = d:6
3. c = 6:d

From equation 2 and 6, we can see that "c" is equal to "d:6," which means "d divided by 6."

Now, let's substitute the values of "a" and "b" into equation 1: A = 9b A = 9(±√6)

So, we have found the values of "A" and "c": A = 9(±√6) c = d/6

The exact values of "A" and "c" would depend on whether you take the positive or negative square root for "b." So, you have two sets of solutions for A and c:

1. A = 9√6, c = d/6
2. A = -9√6, c = d/6

These are the solutions to the given equations.