Question

(0,2t + 0,3s) (0,04t^2 - 0,06ts + 0,09s​

Answer 1

Ответ:

Вычисление

$\left(\frac{t}{5}+\frac{3s}{10}\right)\left(-\frac{3st}{50}+\frac{t^{2}}{25}+\frac{9s}{100}\right)$

Разложение

$-\frac{9ts^{2}}{500}+\frac{t^{3}}{125}+\frac{9st}{500}+\frac{27s^{2}}{1000}$

Answer 2

To multiply the expressions (0.2t + 0.3s) and (0.04t^2 - 0.06ts + 0.09s), you can use the distributive property or the FOIL method (First, Outer, Inner, Last). Here's how you can do it step by step:

(0.2t + 0.3s)(0.04t^2 - 0.06ts + 0.09s)

First, multiply the terms in the first expression by each term in the second expression:

First: (0.2t)(0.04t^2) = 0.008t^3 Outer: (0.2t)(-0.06ts) = -0.012ts^2 Inner: (0.3s)(0.04t^2) = 0.012t^2s Last: (0.3s)(-0.06ts) = -0.018ts^2

Now, add up all these results:

0.008t^3 - 0.012ts^2 + 0.012t^2s - 0.018ts^2

Finally, combine like terms:

0.008t^3 + (0.012t^2s - 0.018ts^2)

So, the product of (0.2t + 0.3s) and (0.04t^2 - 0.06ts + 0.09s) is:

0.008t^3 + 0.012t^2s - 0.018ts^2